Conical frustum calculator

Volume, slant height and surfaces of a truncated cone from two radii and the height.

Inputs

Conical frustum calculator

4 fields

A right circular frustum with parallel circular bases and one common axis. Total surface includes both bases; wall thickness, rim and partial filling are not modelled. Capacity needs internal dimensions in one selected unit.

Fill in the fields and the result will appear here automatically.

A right circular frustum has concentric parallel bases and a perpendicular height. Its volume V = πh(R²+Rr+r²)/3 accounts for a radius changing continuously with height. Slant height l = √(h²+(R−r)²) follows the lateral surface; substituting h for l understates that area. This tool uses R > r ≥ 0: enter the larger radius first, while a zero smaller radius gives a full cone.

FAQ
5 questions
Freshness
formula-based

How it works

Formula and logic

Volume V = πh(R² + Rr + r²)/3. Slant height l = √(h² + (R − r)²). The lateral surface is π(R + r)l, and the total surface adds both bases.

Example

A frustum with radii of 6 and 3 cm and a height of 8 cm has a volume of 527.79 cm³.

Fields and units

  • Length unit — list option
  • Larger radius — cm
  • Smaller radius — cm
  • Height — cm

How to use

  • — Choose the length unit.
  • — Enter the larger base radius R.
  • — Enter the smaller radius r regardless of the solid’s orientation.
  • — Enter the height: the vertical distance between the bases, not the slant.

Method and limitations

Calculation method
Formula and logic
Limitation
A right circular frustum with parallel circular bases and one common axis. Total surface includes both bases; wall thickness, rim and partial filling are not modelled. Capacity needs internal dimensions in one selected unit.

FAQ

How is the height different from the slant height?

Height h is perpendicular to the bases; slant l follows the surface. With unequal radii l > h, so π(R+r)h is smaller than the correct lateral area π(R+r)l.

Where does the Rr term in the volume come from?

Cross-section radius changes linearly, while its area is quadratic. Integrating π[R+(r−R)z/h]² from 0 to h gives πh(R²+Rr+r²)/3. Averaging the base areas instead overstates volume by πh(R−r)²/6.

What happens if the top radius is zero?

You get an ordinary cone, and the formula reduces to πR²h/3. That makes a convenient check on the result.

Why must the top radius be smaller than the bottom one?

That is this tool’s input order, not a restriction on how a solid can be oriented. Enter the larger radius as R and the smaller as r regardless of how the vessel stands. Equal radii are excluded here; use the cylinder calculator for that case.

How do I work out what a bucket holds?

Enter the radii of the base and the rim and the inside height. The volume in cubic centimetres divided by 1000 gives litres.